You could probably find a way to do this using nls(), optim() or uniroot() but this seems to be very much a homework problem so I won't say more.
solve() solves matrix linear equations... not what you want here. Read the docs. Michael On Thu, May 17, 2012 at 2:53 PM, Pei-Ling Lin <barthea...@gmail.com> wrote: > Hi all, > > I need to solve this following equation which the unknown value (here is "a") > is on the exponent place, could anybody please help me to figure it out? I > tried to use lm.sol() or solve() function but it doesn't work...... > > Thanks for help, > Peiling > > > (x, y) = (2.21, 1.01) > > y = 1 + x - ( 1 + (x)^a)^(1/a) > > > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
