You're thinking about it wrong. This is an arithmetic sequence: seq(from = 1000, by = -30, length.out = 15)
Michael On Fri, Apr 20, 2012 at 5:14 AM, uday <uday_143...@hotmail.com> wrote: > I would like to calculate vector from existing value > e.g > v <- 1000 > s <- 30 > d1 <- v-s > d1 <- 970 > d2 <- d1 -s > d2 <- 940 > d 3 <- d2-s > d3 <- 910 > : > : > d15 <- ..... > > so how I should get vector of length 15 d < - 970,940 , 910 , > ....... > > -- > View this message in context: > http://r.789695.n4.nabble.com/vector-subtraction-tp4573299p4573299.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
