Hello, I can get the median for each factor, but I'd like another column to go with each factor. The nm column is a long name for the lvls column. So unique work except for the order can get messed up.
Example: x = data.frame(val=1:10,lvls=c('cat2',rep("cat1",4),rep("cat2",4),'cat1'),nm=c('longname2',rep("longname1",4),rep("longname2",4),'longname1')) x val lvls nm 1 1 cat2 longname2 2 2 cat1 longname1 3 3 cat1 longname1 4 4 cat1 longname1 5 5 cat1 longname1 6 6 cat2 longname2 7 7 cat2 longname2 8 8 cat2 longname2 9 9 cat2 longname2 10 10 cat1 longname1 unique doesn't work in data.frame: mdn = do.call(rbind,lapply(split(x[,1], x[,2]), median)) data.frame(mdn,ln=as.character(unique(x[,3]))) mdn ln cat1 4 longname2 cat2 7 longname1 I want: mdn ln cat1 4 longname1 cat2 7 longname2 Thank you very much! PS - looking for simple'ish solutions. I know I can do it with loops and merges, but is there an option I am not using here? Ben [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.