>>>>> "LS" == Libo Sun <libo...@rams.colostate.edu>
>>>>> on Tue, 21 Feb 2012 21:09:54 -0700 writes:
> Thanks. Shall I sum the user time and system time, which
> roughly equals to the elapsed time?
No. Rather just use the user time,
i.e. proc.time()[[1]]
system.time()[[1]] etc
That's typically good enough [as long as you don't use
internally multithreaded BLAS, or parallelize / distribute your job,
or other things you won't be doing (yet)].
Martin Maechler, ETH Zurich
> I also tried to improve the code by using 'cmpfun(myfunction)' in
> 'compiler' package, however, it doesn't help too much.
> Libo
> On Tue, Feb 21, 2012 at 8:11 PM, R. Michael Weylandt <
> michael.weyla...@gmail.com> wrote:
> The time relationships aren't strictly linear between any of the three
> measures, but *very generally* I've interpreted them as something
> like:
>
> User: stuff you do (i.e., doing all the commands)
> System: stuff at the OS level (memory allocations and whatnot)
> Elapsed: Clock time
>
> None is a great measure in isolation, but the system time is not the
> worrisome one here: it looks like your script takes about a day and a
> half to run....that might be ok (and perhaps unavoidable) but it looks
> like there might be value in trying to squeeze some speed out of your
> script. A simple thing like byte-compiling that gives 2x speedup would
> be huge here.
>
> Michael
>
> On Tue, Feb 21, 2012 at 10:06 PM, Libo Sun <libo...@rams.colostate.edu>
> wrote:
> > Hi all,
> >
> > I got this time for my code,
> >
> >> proc.time()-pt
> > user system elapsed
> > 132541.743 0.004 132533.526
> >
> > As you can see, there is huge difference btw elapsed time and system
> time.
> > Does that mean lots of I/O? Or some bad coding?
> >
> > Thanks,
> > Libo
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