On 12-02-03 11:10 AM, G See wrote:
Sorry, I meant
Do you know of a way to print a string such that I can see whether it
contains a *space* or a no-break space?
Use tools::showNonASCII(x). On Petr's example, it gives
1: n/a<c2><a0>
Duncan Murdoch
On Fri, Feb 3, 2012 at 10:10 AM, G See<gsee...@gmail.com> wrote:
Petr,
Thank you! That is great.
Do you know of a way to print a string such that I can see whether it
contains a string or a no-break space?
Thanks,
Garrett
On Fri, Feb 3, 2012 at 10:01 AM, Petr Savicky<savi...@cs.cas.cz> wrote:
On Fri, Feb 03, 2012 at 09:25:10AM -0600, G See wrote:
I have a data.frame named "df". The dput of df is at the bottom of this e-mail.
What I'd like to do is replace the "n/a " values with NA. On Mac OSX, it works
to do this:
df[df == "n/a"]<- NA
However, it does not work on Ubuntu. See below.
Thanks in advance,
Garrett
x<- df[27, 4] # complete data.frame dput is below
dput(x)
"n/a "
Hi.
This string contains a no-break space, not a space.
"n/a " == "n/a\uA0"
[1] TRUE
"n/a\uA0"
[1] "n/a "
Hope this helps.
Petr Savicky.
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