In an earlier post, a person wanted to divide each of the rows of rawdata by the row vector sens so he did below but didn't like it and
asked if there was a better solution. rawdata <- data.frame(rbind(c(1,2,2), c(4,5,6))) sens <- c(2,4,6) temp <- t(rawdata)/sens temp <- t(temp) print(temp) Gabor sent three other solutions and I understood 2 of them but not the one below. I think I understand mapply a little but what I don't understand how it knows to take the rows of rawdata and then I guess recycle sens ? how did the mapply know not to take the columns of rawdata and do something to them ? or maybe mapply does things element by element and it is doing more complex recycling ? I guess I don't really understand mapply that well but I did read the help of it. Thanks so much for any enlightenment from anyone besides Gabor. I bother him enough already and he does more than enough. tempc <- data.frame(mapply("/", rawdata, sens)) print(tempc) Mark [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.