Reread ?lm and note that the lhs can be a matrix. I believe this is exactly what you want.
-- Bert On Sun, Jan 29, 2012 at 2:05 PM, Martin Batholdy <batho...@googlemail.com> wrote: > Hi, > > > I would like to fit lm-models to a matrix with 'samples' of a dependent > variable (each row represents one sample of the dependent variable). > The independent variable is a vector that stays the same: > > > y <- c(1:10) > x <- matrix(rnorm(5*10,0,1), 5, 10) > > > > now I would like to avoid looping over the rows, since my original matrix is > much larger; > > > > for(t in 1:dim(x)[1]) { > > print(lm(y ~ x[t,])) > > } > > > Is there a time-efficient way to do this? > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. -- Bert Gunter Genentech Nonclinical Biostatistics Internal Contact Info: Phone: 467-7374 Website: http://pharmadevelopment.roche.com/index/pdb/pdb-functional-groups/pdb-biostatistics/pdb-ncb-home.htm ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.