On Jan 24, 2012, at 11:07 AM, Dan Abner wrote:

Hi everyone,

I am using Michael's approach (grepl()) to identify which columns
containing $ signs. I was hoping to incorporate this into a line of
code that would automatically 1) find which columns contain $ signs,
2) strip the $ and commas, and 3) convert the result to a numeric
vector.

I have the following:

col.id<-function(x) any(grepl("\\$",x))


No data to test so ... no testing: Perhaps ...

cand2[which(sapply(cand2,col.id))] <-
        sapply( cand2[which(sapply(cand2,col.id))],
function(cols) as.numeric(gsub("[$,]", "", cols)) )

### amen to Michael's admonition--------
PS -- Stop with HTML postings (seriously, it actually does mess up
what the rest of us see and I think it causes trouble for the archives
as well)
###-----------------

However, I am doing something wrong: while the code correctly
identifies the columns containing $ signs, it also returns ALL NA for
those columns.

See my initial message for this thread for example data.

Any assistance is appreciated.

Thanks!

Dan


On Tue, Jan 24, 2012 at 9:04 AM, R. Michael Weylandt
<michael.weyla...@gmail.com> wrote:
Either

any(grepl("$",x, fixed = TRUE)) # You probably want grepl not grep
any(grepl("\\$",x) )
? regexpr # $ has a special value

Michael



On Tue, Jan 24, 2012 at 8:49 AM, Dan Abner <dan.abne...@gmail.com> wrote:
Hello everyone,

I am writing my own function to return the column index of all variables (these are currently character vectors) in a data frame that contain a
dollar sign($). A small piece of the data look like this:

can_sta can_zip ind_ite_con ind_uni_con AL 36106 $251,895.80 $22,874.43
AL 35802 $141,373.60 $7,100.00  AL 35201 $273,208.50 $18,193.66  AR
72404 $186,918.00
$25,391.00 AR 72217 $451,127.00 $27,255.23 AR 7.28E+08 $58,336.22 $5,293.82


So far I have:


col.id<-function(x) any(grep("$",x))
sapply(cand2,col.id)

However, this returns TRUE for all columns (even those that do not contain
the $).

Any assistance is appreciated.

Thank you,

Dan

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