On Tue, Mar 18, 2008 at 12:05:23PM +0100, Albert Greinoecker wrote: > try: > aggregate(d[,2:3], by=list(d$foo), FUN=sum)
Great! Now I can get a data.frame as well as a list, thanks!
--
Hans Ekbrand (http://sociologi.cjb.net) <[EMAIL PROTECTED]>
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