Fit y-b without an intercept? (which you do by adding "+ 0" or "- 1" to the model formula) Not sure if this is the optimal result, but it will give you a pretty reasonable answer.
Michael On Thu, Dec 8, 2011 at 10:52 AM, Alaios <ala...@yahoo.com> wrote: > Dear all, > I have a formula of the form > y=ax+b > I know everything except b. How I can ask R to do fitting to find only the > value of b? > I already know the lm() but it always return both an intercept point (b) and > the a. > > What should I do ? > > I would like to thank you in advance for your help > > B.R > Alex > > [[alternative HTML version deleted]] > > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
