Similarly, this might work:
unlist(lapply(Version1_, `[`,"First"))
Michael
On Thu, Dec 1, 2011 at 9:41 PM, Sarah Goslee <sarah.gos...@gmail.com> wrote:
> How about:
>
> lapply(Version1_, subset, subset=c(TRUE, FALSE))
> or sapply() depending on what you want the result to look like.
>
> Thanks for the reproducible example.
>
> Sarah
>
> On Thu, Dec 1, 2011 at 5:17 PM, LCOG1 <jr...@lcog.org> wrote:
>> Hi everyone,
>> I looked around the list for a while but couldn't find a solution to my
>> problem. I am storing some results to a simulation in a list and for each
>> element i have two separate vectors(is that what they are called, correct my
>> vocab if necessary). See below
>>
>> Version1_<-list()
>> for(i in 1:5){
>> Version1_[[i]]<-list(First=rnorm(1),Second=rnorm(1))
>> }
>>
>> What I want is to put all of the elements' 'First' vectors into a single
>> list to box plot. But whats a more elegant solution to the below?
>>
>> c(Version1_[[1]]$First,Version1_[[2]]$First,Version1_[[3]]$First,Version1_[[4]]$First,Version1_[[5]]$First)
>>
>> since i have 50 or more simulations this is impractical and sloppy. Do I
>> need to store my data differently or is their a solution on the back end?
>> Thanks all.
>>
>> Josh
>>
> --
> Sarah Goslee
> http://www.functionaldiversity.org
>
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