chuck.01 wrote > > > datum <- structure(list(Y = c(415.5, 3847.83333325, 1942.833333325, > 1215.22222233333, > 950.142857325, 2399.5833335, 804.75, 579.5, 841.708333325, 494.053571425 > ), X = c(1.081818182, 0.492727273, 0.756363636, 0.896363636, > 1.518181818, 0.499166667, 1.354545455, 1.61, 1.706363636, 1.063636364 > )), .Names = c("Y", "X"), row.names = c(NA, -10L), class = "data.frame") > > with(datum, plot(Y~X)) > > As you can see there is a non-linear association between X and Y, and I > would like to fit an appropriate model. I was thinking an exponential > decay model might work well. > I tried the following (a and k starting values are based off of a lm() > fit), but get an error. > > fit <- nls(Y ~ a*exp(-k * X), datum, start=c(a=3400, k=1867)) > > Error in nlsModel(formula, mf, start, wts) : > singular gradient matrix at initial parameter estimates >
Try plot(datum$X,datum$Y) For more complex cases, plot the initial function you are trying to fit, but in this case it is easy to see that k is more in the order of 2. So try with k=2. Dieter -- View this message in context: http://r.789695.n4.nabble.com/nls-help-tp4123876p4124164.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.