Whenever similar objects are to be handled with similar code, having the data 
frames stored in lists or even as one big data frame is preferred. If you can 
load them as such, half the complexity is addressed right there.
The for loop processing is usually wrapped up using base apply functions or 
"plyr" package functions. Those  idioms are not necessarily faster than for 
loops, but they can wrap up some common split and assemble steps cleanly.
---------------------------------------------------------------------------
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DCN:<jdnew...@dcn.davis.ca.us>        Basics: ##.#.       ##.#.  Live Go...
                                      Live:   OO#.. Dead: OO#..  Playing
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Sent from my phone. Please excuse my brevity.

Kaiyin Zhong <kindlych...@gmail.com> wrote:

>> for (d in paste('df', 1:3, sep='')) {
>+  assign(d, as.data.frame(replicate(3, rnorm(4))))
>+ }
>> dats = list(df1,df2,df3)
>> for (i in 1:length(dats)) {
>+  names(dats[[i]]) = c('w', 'l', 'h')
>+ }
>> dats
>[[1]]
>            w           l           h
>1  1.24319239 -0.05543649  0.05409178
>2  0.05124331 -1.89346950  0.33896273
>3 -1.69686777 -0.35963008 -0.91720034
>4  1.30786112 -0.23953238  0.94139356
>
>[[2]]
>          w           l          h
>1 -1.238519 -0.12352187 -1.2577607
>2  1.180469  2.38836107  2.9139199
>3  1.494369 -0.07088712  0.2372746
>4  1.942535  1.47911615  1.1431675
>
>[[3]]
>           w          l          h
>1  1.0198692 -1.4222194  1.9486072
>2  0.3057461  1.7630326 -0.6501801
>3 -0.5576854 -1.1637263 -0.1782680
>4  0.6625268  0.6913202  0.9588915
>> i = 1
>> for (n in paste('df', 1:3, sep='')) {
>+  assign(n, dats[[i]])
>+  i = i+1
>+ }
>> df1
>            w           l           h
>1  1.24319239 -0.05543649  0.05409178
>2  0.05124331 -1.89346950  0.33896273
>3 -1.69686777 -0.35963008 -0.91720034
>4  1.30786112 -0.23953238  0.94139356
>
>       [[alternative HTML version deleted]]
>
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