If you want fitted() to return NAs in the positions where
there were NA's in data, use na.action=na.exclude in your
call to lm(). E.g.,
> z <- data.frame(y=1:5, x=c(1,NA,3,3,5))
> fitted(lm(y~x, data=z))
1 3 4 5
1.25 3.25 3.25 5.25
> fitted(lm(y~x, data=z, na.action=na.exclude))
1 2 3 4 5
1.25 NA 3.25 3.25 5.25
I think the help file for model.matrix has more detail,
including how to use options() to set the na.action for
your R session.
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -----Original Message-----
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf Of arunkumar1111
> Sent: Monday, November 14, 2011 3:36 AM
> To: r-help@r-project.org
> Subject: Re: [R] help in fitted values in lm function
>
> Yes there are few NA in the Data
>
> --
> View this message in context:
> http://r.789695.n4.nabble.com/help-in-fitted-values-in-lm-function-
> tp4038642p4039207.html
> Sent from the R help mailing list archive at Nabble.com.
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
