This is probably what you want: > outLength <- lapply(outputList, function(x)length(strsplit(x, ' ')[[1]])) > outLength [[1]] [1] 4
[[2]] [1] 4 > notice that 'outputList' is a 'list' and not a legal argument to strsplit. On Thu, Nov 10, 2011 at 5:29 AM, vioravis <viora...@gmail.com> wrote: > I am using gsub to remove numbers for each element of a list. Code is given > below. > > testList <- list("this contains a number 1000","this does not contain") > removeNumbers <- function(X) > { > gsub("\\d","",X) > } > outputList <- lapply(testList,removeNumbers) > > However, when I try to find the number of words in outputList as follows > > outLength <- lapply(strsplit(outputList," "),length) > > it throws out the following error: > > Error in strsplit(outputList, " ") : non-character argument > > > Can someone help me with this? > > Thank you. > > Ravi > > -- > View this message in context: > http://r.789695.n4.nabble.com/Removing-numbers-from-a-list-tp4023074p4023074.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Jim Holtman Data Munger Guru What is the problem that you are trying to solve? Tell me what you want to do, not how you want to do it. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.