Hi:
I'd double check the form of the upper bound of the sequence. In the
first case (i = 1), it uses the subvector loghozamok[1:220]; when i =
2, it uses the subvector loghozamok[21:260], etc. In the last case, it
uses loghozamok[1181:1420]. If instead you want to split the vector
into 60 groups of size 20, then this is easier (assuming that
loghozamok has length 1200):
gp <- rep(1:60, each = 20)
# Returns a vector
do.call(c, lapply(split(loghozamok, gp),
function(z) unname(tseries::jarque.bera.test(z)$p.value)))
This works when gp and loghozamok have the same length.
# Small test:
x <- rnorm(100)
gp <- rep(1:5, each = 20)
do.call(c, lapply(split(x, gp),
function(z) unname(tseries::jarque.bera.test(z)$p.value)))
1 2 3 4 5
0.5849843 0.6745735 0.9453412 0.5978477 0.7207138
HTH,
Dennis
On Sun, Oct 30, 2011 at 10:23 AM, Szűcs Ákos <szucsa...@t-online.hu> wrote:
> Hi!
> I got a loop where i print out the results of Jarque Bera tests, but I have
> to put, the p-values in a vector. Can you help me how to do it in an
> effective way and not just typing in the results to a vector? Thanks a lot,
> here is the code:
> for(i in 1:60){
> print(jarque.bera.test(loghozamok[((20*(i-1))+1):(20*(i+11))]))}
>
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