On Oct 14, 2011, at 5:11 AM, Petr PIKAL wrote:
Hi
I have a related question...I have a data frame similar with 74 rows
that I
created with "header=TRUE", but when I try to coerce one of the data
frame
columns into a vector, it shows up as having length 1, even though
when
I
print it, it shows 74 elements:
VAL <- c(DailyDiary[1])
VAL
[1] 3 3 3 2 3 3 4 4 3 3 2 1 1 4 3 3 2 3 3 2 2 3 3 3 1 2 2
[28] 1 1 3 3 3 2 4 3 2 3 4 3 3 3 3 4 3 2 3 2 3 1 2 1 2 3 1
[55] 0 3 2 4 3 1 2 3 1 1 1 4 3 2 1 2 3 3 3 2
length(VAL)
[1] 1
your VAL is still data frame. See ?"[" and link to data.frame
method. Use
str(object)
Or at least a list. The "c" function stripped its attributes:
> str( c( data.frame(a=1:10) ) )
List of 1
$ a: int [1:10] 1 2 3 4 5 6 7 8 9 10
Which also is an explanation for why its length is still reported as 1.
to see the structure of your object not just printing it to console as
print is a function which has also different methods for different
objects
and does not inform you about nature of your object.
You shall profit from reading R-intro which I believe you have
overlooked.
It shall be installed in doc/manual directory of your R installation.
Regards
Petr
On the other hand, I can easily coerce the row names to a vector of
length
74
partf <- row.names(DailyDiary)
length(partf)
[1] 74
What I would like to do is make VAL into a vector with length 74
instead
of
length 1 so I can sort it using use "partf" as factors. I tried
"as.vector", but it doesn't let you specify the length. Any ideas?
One might think that as.vector might be able to extract a vector from
a list if length 1 but one would be wrong and should then got to :
?unlist
Thanks,
and sorry if I'm being unclear or stupid, I'm a newbie :)
Logan
David Winsemius, MD
West Hartford, CT
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