Hi Alex,
If "data" is a matrix, probably the easiest option would be:
tips <- as.data.frame(data)
mclapply(tips, foo)
By the way, I would recommend not using 'data' (which is also a
function) as the name of the object storing your data. If your data
set has many columns and performance is an issue I might convert it to
a list instead of a data frame. Note that if you wanted the
equivalent of apply(tips, 1, foo), you could transpose your matrix
first: as.data.frame(t(data)). lapply works on columns of a data
frame because each column is basically an element of a list (list
apply).
Cheers,
Josh
On Sun, Oct 9, 2011 at 8:47 AM, Alaios <ala...@yahoo.com> wrote:
> Dear all I want to convert a apply to lapply. The reason for that is that
> there is a function mclappy that uses exact the same format as the lapply
> function.
>
> My code looks like that
>
> mean_power_per_tip <- function(data) {
> return((apply(data[,],2,MeanTip)));
> }
>
> where data is a [m,n] matrix.
>
> I would like to thank you in advance for your help
>
> B.R
> Alex
>
> [[alternative HTML version deleted]]
>
>
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>
--
Joshua Wiley
Ph.D. Student, Health Psychology
Programmer Analyst II, ATS Statistical Consulting Group
University of California, Los Angeles
https://joshuawiley.com/
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