I think that your 'C' column is a factor(or character), because the
character used(comma).
One option:
dat$C <- as.numeric(gsub(",", ".", as.character(dat$C)))
library(doBy)
summaryBy(C ~ B, data=dat, FUN=c(median, var), na.rm = T)
On 09/03/2008, Agrarimmobilien <[EMAIL PROTECTED]> wrote:
> Hello,
>
> I try to transform a data frame like
>
> A B C
>
> 1 1 2,5
> 2 2 NA
> 3 1 1,0
> 4 1 56
> 5 2 23
> 6 1 NA
> 7 2 46
>
> to the following dataframe, calculating the variance and median of the
> C-column, group by B, so the result will be:
>
> B C(median) D (var)
> 1 19,83 9
> 2 34,5 21
>
>
> Doing this, I got problems with the NAs in column C.
> I tried to combine the aggregate - function
> aggregate(C, list(B), FUN=(mean, var))
>
> with the following functions
>
> var(C, use="complete.obs")
> median(C, rm.na=TRUE)
>
> but it doesn't work as I want. Has anybody an idea how to do this work?
>
> thank you
> Iksmax
>
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>
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
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