regexpr() can be used instead of regMatchPos() in S+ and
R. (It has been in S+ longer than regMatchPos.)
Instead of using regexpr and substring I usually use sub()
or gsub(). E.g., since S+ 8.0 and a long time ago in
R you can do
x <- c("Cycle 1 Day 15 Hour 2", "Cycle 2 Day 3")
sub("^.*Day +([[:digit:]]+).*$", "\\1", x)
to get "15" and "3".
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -----Original Message-----
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf Of Michael Karol
> Sent: Tuesday, September 27, 2011 2:49 PM
> To: r-help@r-project.org
> Subject: [R] Equivalent to regMatchPos in R.
>
> R Experts:
>
>
>
> I am trying to isolate the numeric value of day from a string that might
> look like "Cycle 1 Day 8" or "Cycle 12 Day 15".
>
>
>
> In essence, what I need is a function that can look at a character
> string and tell me the location within the string where it matches with
> a given string. In this case, where within "Cycle 12 Day 15" is the
> text "Day" located.
>
>
>
> The following works in S+, but I haven't been able to locate a function
> within R that does what regMatchPos does in S+.
>
> (If possible, I'd like a function that works in both.)
>
>
>
> Can someone please help?
>
>
>
>
>
> PKTimes$Day <- substring( PKTimes$Visit,
> regMatchPos(PKTimes$Visit,"DAY")[,2] +2, nchar(PKTimes$Visit )
>
>
>
> Thanks,
>
> Michael
>
>
>
>
> [[alternative HTML version deleted]]
>
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