Hi all This is probably a simple problem but somehow I am having much trouble with finding a solution, so I seek your help!
I have a data-set with continuous response variables. The explanatory variably is 4xpH treatments (so 8.08, 7.94, 7.81 and 7.71) so also continuous and not technically factorial. However I have decided to do Anova's (as well as regression) to explore the effect of pH. What I don't understand is why the anova done in such a way: summary(aov(BioMass~pH)) ... gives me completely different p-values if I define the pH as factor or not. And what would be the correct approach? Help on this subject would be much appreciated! Hronn -- View this message in context: http://r.789695.n4.nabble.com/ANOVA-define-as-factor-or-not-tp3846861p3846861.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
