It is not simply the answer, it is a list str(integrate(dnorm, -1.96, 1.96)) List of 5 $ value : num 0.95 $ abs.error : num 1.05e-11 $ subdivisions: int 1 $ message : chr "OK" $ call : language integrate(f = dnorm, lower = -1.96, upper = 1.96) - attr(*, "class")= chr "integrate"
Is this what you want (?): 1 + (integrate(dnorm, -1.96, 1.96)[[1]]) ChrisQ wrote: > > Hi, > > I need to do a calculation in R which involves adding the estimate of a > numerical integration with another number - however, if I add the number > to > the output of the intergrate function (which when run on its own provides > me > with a number with error), I get the message 'non-numeric argument to > binary > operator'. How would I be able to avoid this and use the estimate? > > eg: I have the code integrate(dnorm, -1.96, 1.96), which gives the output > 0.9500042 with absolute error < 1.0e-11, but if I put in integrate(dnorm, > -1.96, 1.96)+1, I don't get 1.9500042 - how would I? > > Thanks very much, Chris. > > -- > View this message in context: > http://r.789695.n4.nabble.com/Help-with-Integration-Output-tp3839360p3839360.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- View this message in context: http://r.789695.n4.nabble.com/Help-with-Integration-Output-tp3839532p3839552.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
