On Sep 15, 2011, at 1:50 PM, Mike Treglia wrote:
Dear List Members,
I have created a function to run a simulation based on a given set
of values within a vector, such that I run the function like this:
new.data<-sapply(vector, function)
In which I run 'function' on every value within a vector that I
created. The result is a matrix of 1000 rows, and as many columns as
the length of the vector.
I modified the function to utilize two given values, such that it
is: function(x,y), and I want to run this function for not only a
range of values of 'x', but a range of values of 'y' as well, such
that for each value of 'y', I'd create another 1000 rows in the
matrix. I was trying to loop this, but in doing so, it looks like I
just keep creating datasets and replacing them with datasets for
subsequent 'y' values, rather than adding new rows. The structure of
my current loop is below. Any suggestions on what to change to
accomplish what I want? Would it be good to create a dataframe first
and then somehow add these new rows to the dataframe? Also, is it
appropriate to have the 'i' in the sapply statement?
for (i in c(seq(10,100,10))){
The c() call is extraneous.
new.data<-sapply(vector, function, i)
Perhaps:
# scrap the entire for loop(sapply()) mess and use this
newdata <- outer(Y=seq(10,100,10), X=vector, FUN=function)
Or:
mapply(function, expand.grid(x=vector, y=seq(10,100,10) ) )
# which is sort of like your last notion,
All of this is untested in the absence of a reproducible example but
you definitely should work through the examples on:
?outer
?mapply
}
Please let me know if more detail on my code would be helpful- I was
just trying to keep it simple and focus on what I saw as the problem
at hand for now.
Thank you for your help.
Sincerely,
Mike Treglia
--
Michael Treglia
Applied Biodiversity Sciences NSF-IGERT Program
Wildlife and Fisheries Sciences
Texas A&M University
Lab: (979)862-7245
ml...@tamu.edu
http://people.tamu.edu/~mlt35
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David Winsemius, MD
West Hartford, CT
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