Hi
I need to use rep() to get a vector out, but I have spotted something very
strange. See the reproducible example below.
N <- 79
seg <- 5
segN <- N / seg # = 15.8
d1 <- seg - ( segN - floor(segN) ) * seg
d1 # = 1
rep(2, d1) # = numeric(0), strange - why doesn't it print one "2"?
rep(2, 1) # 2, ok
rep(2, d1 / 1,1) # 2, this does work
rep(2, d1 + 2) # "2 2" - also works but...
d1 + 2 # = 3! so why does it print two 2s above?
d1 == 1 # FALSE
all.equal(d1, 1) # TRUE
identical(d1, 1) # FALSE
Try something else...
d2 <- 4 - ( (79/4) - floor(79/4))* 4
d2 # = 1
rep(2, d2) # 2 : this works!
d2 == 1 # TRUE
all.equal(d2, 1) # TRUE
identical(d2, 1) # TRUE
#version info
platform x86_64-pc-linux-gnu
arch x86_64
os linux-gnu
system x86_64, linux-gnu
status
major 2
minor 10.1
year 2009
month 12
day 14
svn rev 50720
language R
version.string R version 2.10.1 (2009-12-14)
Seems like there's some binary maths errors here somewhere. Very strange to
me. Anyway, I need to be able to use the result d1 in a rep() command. Any
way to force rep not to be *too* specific in how it reads its "times"
argument?
Thanks in advance,
Benjamin Hoyer
DTU MSc Mathematical Modelling (2012) / Novozymes student helper
[[alternative HTML version deleted]]
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
