This is my reproducible example: example<-structure(list(SENSOR = structure(1:6, .Label = c("A", "B", "C", "D", "E", "F"), class = "factor"), VALUE = c(270, 292.5, 0, 45, 247.5, 315), DATE = structure(1:6, .Label = c(" 01/01/2010 1", " 01/01/2010 2", " 01/01/2010 3", " 01/01/2010 4", " 01/01/2010 5", " 01/01/2010 6"), class = "factor")), .Names = c("SENSOR", "VALUE", "DATE"), class = "data.frame", row.names = c("1", "2", "3", "4", "5", "6"))
I need to resahpe "example" in a wide format so that “SENSOR” appear as columns and “DATE” as rows with corresponding “VALUE” as value; I thought it was very simple so that I’ve been trying this: dcast(example,DATE~SENSOR) But I've got this message: Using DATE as value column. Use the value argument to cast to override this choice Errore in `[.data.frame`(data, , variables, drop = FALSE) : undefined columns selected and even if by using the value argument sorted out any good result… sorry for the very trivial question, I've been looking at documentation and forums anywhere but I was not successful at all and now I’m somehow in the right middle of nowhere… any help or hint for this? thank you max -- View this message in context: http://r.789695.n4.nabble.com/reshape-data-from-long-to-wide-format-tp3801381p3801381.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.