Hi: I don't know if this is what you meant but here's a way to cheat and do it.
1) back out the [sigma over sqrt root of n] from the 95 % CI and call it X. 2) then generate data using rnorm(n*, known mean, sigma*) where sigma*/sqrt(n*) = X is satisfied. 3) there will be many solutions to 2) so you could make up a sigma* and then back out the n* that makes it hold. On Wed, Sep 7, 2011 at 10:22 PM, Rolf Turner <rolf.tur...@xtra.co.nz> wrote: > On 08/09/11 09:51, Tyler Hicks wrote: >> >> Is there a function in R that will generate data from a known mean and 95% >> CI? I do not know the distribution or sample size of the original data. > > No. R is wonderful, but it cannot work magic. > > cheers, > > Rolf Turner > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
