Am Donnerstag, den 06.03.2008, 17:47 +0100 schrieb Petr PIKAL: > Hi > > [EMAIL PROTECTED] napsal dne 06.03.2008 17:41:06: > > > Hi there, > > > > When i do > > > > mean(fl[1:20], na.rm=T) > > e.g. > > sum(!is.na(fl[1:20]))
This seems to give me a sum of all the items.
But I'd like to have it per column.
> mean(fl[1:20])
aids angststoer autismus bauchspduekrebs
prostata
-0.7474884 -1.0475500 -0.6267267 NA
-1.7318179
fraudep manndep hautkrebs herzinfarkt
leukaemie
-1.2919841 -1.5124280 -0.3202036 -0.8246589
0.7550549
lungenkrebs manischdepresiv magenkrebs magersucht
mannmagsucht
-1.2451753 -1.9726160 1.4548394 -0.6242250
NA
osteoporose panik schizophrenie schlaganfall
zwangsstoer
-1.7974270 NA -1.8634089 NA
-1.5056106
> mean(fl[1:20], na.rm=T)
aids angststoer autismus bauchspduekrebs
prostata
-0.7474884 -1.0475500 -0.6267267 1.2168804
-1.7318179
fraudep manndep hautkrebs herzinfarkt
leukaemie
-1.2919841 -1.5124280 -0.3202036 -0.8246589
0.7550549
lungenkrebs manischdepresiv magenkrebs magersucht
mannmagsucht
-1.2451753 -1.9726160 1.4548394 -0.6242250
-0.3765245
osteoporose panik schizophrenie schlaganfall
zwangsstoer
-1.7974270 -1.2328361 -1.8634089 -1.7165059
-1.5056106
> sum(!is.na(fl[1:20]))
[1] 892
So I'd like to have it like the mean, to see how many data is calculated
by na.rm=T per column?
Thanks,
Martin
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