I definitely used too much lines s of code because I still don't know how to
do some staff.
but it works:
seq=5 #starting value
var=5 # starting value
long= 1:10 # length of the vector
for (x in long){
var=var+((var/100)*40)
seq=append(seq,var)
}
seq=round(seq)
seq=cumsum(seq)
> seq
[1] 5 17 39 75 130 212 332 505 752 1102 1597
Probably I could set just a variable instead of 2 ( var and seq)
and set the value of long directly to 10, but as I said I just started using
R
Thanks :)
?cumsum
> cumsum(yoursequence)
>
> HTH,
> Jorge
>
>
> On Mon, Aug 22, 2011 at 8:36 PM, Claudio Zanettini <> wrote:
>
>> Hello everyone,
>> I would like to generate a sequence
>> such as, starting from 5, every value is
>> 40% of the value before+ all the preceeding values.
>> es:
>> this is the seq of all the value+40% of the preceding value:
>> 5 7 10 14 19 27 38
>> 53 74 103 145 202 283 397
>> 556 778 1089 1525 2134 2988 4183
>>
>> then the vector tha I need is
>> 5 , 5+7, 5+7+10, 5+7+10+14 and so on
>>
>> I can generate the first sequence but I don t know how to generate the
>> last.
>>
>> I would really appreciate your help.
>> Thanks
>> HVZ
>>
>> [[alternative HTML version deleted]]
>>
>> ______________________________________________
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>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>
>
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