Hi Sharad,
Try
xx$newSample <- sapply(with(xx, strsplit(as.character(Sample), "_")), "[", 1)
xx
HTH,
Jorge
On Aug 18, 2011, at 5:43 PM, 1Rnwb wrote:
> I have a data frame like this
> xx<-data.frame(cbind(Sample=c('Ctrl_6h','1+0_6h','1+200_6h','1+5k_6h','Ctrl_5K_6h','ConA_6h'),
> IFIT1=c(24,25,24.7,24.5,24.2,24.8)))
>
> grep('[[:digit:]]h',xx$Sample)
>
> yy<-xx$Sample
>
> strsplit(yy,"_")
>
> I have to extract the time information separated by '_' in the sample names,
> i tried grep and strsplit, it looks that i am not providing some information
> correctly. I would appreciate if someone can point me to the correct way.
> Thanks
> Sharad
>
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