Hi Sharad, Try
xx$newSample <- sapply(with(xx, strsplit(as.character(Sample), "_")), "[", 1) xx HTH, Jorge On Aug 18, 2011, at 5:43 PM, 1Rnwb wrote: > I have a data frame like this > xx<-data.frame(cbind(Sample=c('Ctrl_6h','1+0_6h','1+200_6h','1+5k_6h','Ctrl_5K_6h','ConA_6h'), > IFIT1=c(24,25,24.7,24.5,24.2,24.8))) > > grep('[[:digit:]]h',xx$Sample) > > yy<-xx$Sample > > strsplit(yy,"_") > > I have to extract the time information separated by '_' in the sample names, > i tried grep and strsplit, it looks that i am not providing some information > correctly. I would appreciate if someone can point me to the correct way. > Thanks > Sharad > > -- > View this message in context: > http://r.789695.n4.nabble.com/splitting-sample-names-tp3753712p3753712.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.