Hello list, ## I have been doing the following process to convert data from one form to another for a while but it occurs to me that there is probably an easier way to do this. I am often given data that have column names which are actually data and I much prefer dealing with data that are sorted by factors. So to convert the columns I have previously made use of make.groups() in the lattice package which works completely satisfactorily. However, it is a bit clunky for what I am using it for and I have to carry the other variables forward. Can anyone suggest a better way of converting data like this?
library(lattice) dat <- data.frame(`x1`=runif(6, 0, 125), `x2`=runif(6, 50, 75), `x3`=runif(6, 0, 100), `x4`=runif(6, 0, 200), date = as.Date(c("2009-09-25","2009-09-28","2009-10-02","2009-10-07","2009-10-15","2009-10-21")), yy= head(letters,2), check.names=FALSE) ## Here is an example of the type of data that NEED converting dat dat.group <- with(dat, make.groups(x1,x2,x3,x4)) ## Carrying the other variables forward dat.group$date <- dat$date dat.group$yy <- dat$yy ## Here is an example of what I would like the data to look like dat.group ## The point of this all is so that I can used the data in a manner such as this: with(dat.group, xyplot(data ~ as.numeric(substr(which, 2,2))|yy, groups=date)) ## So I suppose what I am asking is if there is a more efficient way of doing this? Thanks so much in advance! Sam ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.