Hi all, I have a data frame called "rst", see below: ------------------------------------------------------------------------------------------ # This is a paste able example
# In case you don't have "KernSmooth" package installed, please uncomment below line. # install.packages("KernSmooth") library(KernSmooth) rst <- data.frame(hsp = rnorm(23), dal = rnorm(23) gs <- 350 ts <- seq(1, 353, 16) bw <- lapply(rst, dpill, x = ts, gridsize = gs) # If I just want to apply locpoly function seperately lp.hsp <- locpoly(x = ts, y = rst$hsp, bandwidth = bw$hsp, gridsize = gs) lp.dal <- locpoly(x = ts, y = rst$dal, bandwidth = bw$dal, gridsize = gs) -------------------------------------------------------------------------------------------- In above example, I can apply the "locpoly()" to each column of “rst”. But if I want to apply this function to all columns of "rst", I guess I should use lapply() function. However, the "bandwidth", one of the locpoly()'s arguments should be different due to different columns of "rst". It means that when R apply locpoly() to first column "hsp", the "bandwidth" should be set as correspondent bandwidth. My problem is, how to pass the "bandwidth" argument to "locpoly" within lapply() in terms of different column names? My example just tedious if the "rst" has lots of columns. So I wonder if there exist more convenient way to get this job done. Thank you. ----- Richard Ma PhD student, Ecology & Remote Sensing Climate Change Cluster, Department of Environment Science University of Technology, Sydney -- View this message in context: http://r.789695.n4.nabble.com/How-to-pass-different-arguments-to-a-function-within-lapply-tp3728858p3728858.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.