On 07/27/2011 06:28 PM, Francesca wrote:
Dear Contributors,
thanks for collaboration.
I am trying to reorganize data frame, that looks like this:

      n1.Index   Date        PX_LAST    n2.Index   Date.1     PX_LAST.1
n3.Index       Date.2             PX_LAST.2
1     NA        04/02/07    1.34      NA              04/02/07      1.36
        NA              04/02/07      1.33
2     NA        04/09/07    1.34      NA              04/09/07
1.36           NA              04/09/07      1.33
3     NA         04/16/07    1.34      NA             04/16/07      1.36
       NA              04/16/07      1.33
4     NA         04/30/07    1.36      NA             04/30/07
1.40           NA              04/30/07      1.37
5     NA        05/07/07    1.36      NA              05/07/07
1.40           NA              05/07/07      1.37
6     NA         05/14/07    1.36      NA             05/14/07      1.40
       NA              05/14/07      1.37
7     NA         05/22/07    1.36      NA             05/22/07      1.40
       NA              05/22/07      1.37


While what I would like to obtain is:
I would like to obtain stacked data as:

n1.Index       Date        PX_LAST
n1.Index    04/02/07    1.34
n1.Index    04/09/07    1.34
n1.Index     04/16/07    1.34
n1.Index     04/30/07    1.36
n1.Index    05/07/07    1.36
n1.Index     05/14/07    1.36
n1.Index     05/22/07    1.36
n2.Index      04/02/07    1.36
n2.Index     04/16/07    1.36
n2.Index     04/16/07    1.36
n2.Index     04/30/07    1.40
n2.Index     05/07/07    1.40
n2.Index     05/14/07    1.40
n2.Index     05/22/07    1.40
n3.Index     04/02/07    1.33
n3.Index     04/16/07    1.33
n3.Index     04/16/07    1.33
n3.Index     04/30/07    1.37

I have tried the function stack, but it uses only one argument. Then I
have tested the melt function from the package reshape, but it
seems not to be reproducing the correct organization of the data, as
it takes date as the id values.
PS: the n1 index names are not ordered in the original database, so
I cannot fill in the NA with the names using a recursive formula.

Hi Francesca,
Oddly enough, I answered a similar question a few days ago. The function below turns one or more columns in a data frame into two columns, one a factor that defaults to the name(s) of the columns and the other the data that was in that column. It also "stretches" the remaining columns in the data frame to the same number of rows and sticks the two together. It doesn't do exactly what you show above, but it might be good enough. A bit of coding could get the factor levels the way you want.

stretch.var<-function(data,to.stretch,
 stretch.names=c("newvar","scores")) {

 datadim<-dim(data)
 to.rep<-which(!(1:datadim[2] %in% to.stretch))
 nrep<-length(to.rep)
 newDF<-data.frame(rep(data[,to.rep[1]],length(to.stretch)))
 if(nrep > 1) {
  for(repvar in 2:nrep)
   newDF[[repvar]]<-rep(data[[to.rep[repvar]]],length(to.stretch))
 }
 newDF<-cbind(newDF,rep(names(data[,to.stretch]),each=datadim[1]),
  unlist(data[,to.stretch]))
 names(newDF)<-c(names(data[to.rep]),stretch.names)
 rownames(newDF)<-NULL
 return(newDF)
}
# read in the data
fp<-read.table("fp.dat",header=TRUE)
# pass only the columns that you want in the result
stretch.var(fp[,c(2,3,6,9)],2:4,c("n1.index","PX_LAST"))

       Date  n1.index PX_LAST
1  04/02/07   PX_LAST    1.34
2  04/09/07   PX_LAST    1.34
3  04/16/07   PX_LAST    1.34
4  04/30/07   PX_LAST    1.36
5  05/07/07   PX_LAST    1.36
6  05/14/07   PX_LAST    1.36
7  05/22/07   PX_LAST    1.36
8  04/02/07 PX_LAST.1    1.36
9  04/09/07 PX_LAST.1    1.36
10 04/16/07 PX_LAST.1    1.36
11 04/30/07 PX_LAST.1    1.40
12 05/07/07 PX_LAST.1    1.40
13 05/14/07 PX_LAST.1    1.40
14 05/22/07 PX_LAST.1    1.40
15 04/02/07 PX_LAST.2    1.33
16 04/09/07 PX_LAST.2    1.33
17 04/16/07 PX_LAST.2    1.33
18 04/30/07 PX_LAST.2    1.37
19 05/07/07 PX_LAST.2    1.37
20 05/14/07 PX_LAST.2    1.37
21 05/22/07 PX_LAST.2    1.37

Jim

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