On Wed, Jul 27, 2011 at 4:06 AM, steven mosher <mosherste...@gmail.com> wrote: > there are really two related problems here > > I have a 2D matrix > > > A <- matrix(1:100,nrow=20,ncol =5) > > > S <- matrix(1:10,nrow=2,ncol =5) > > > #I want to subtract S from A. so that S would be subtracted from the > first 2 rows of > > #A, then the next two rows and so on. > > > #I have a the same problem with a 3D array > > # where I want to subtract Q for every layer (1-10) in Z > > # I thought I solved this one with array(mapply("-",Z,Q),dim=dim(Z)) > > # but got the wrong answers > > > Z <- array(1:100,dim=c(2,5,10)) > > Q <- matrix(1:10,nrow=2,ncol =5) >
For the first one: matrix(c(t(A)) - c(t(S)), nrow(A), byrow = TRUE) or this version which may seem a bit more complex but has the advantage that it shows the general form of which both your questions are special cases: ix <- 2:1 aperm(array(c(aperm(A, ix)) - c(t(S)), dim(A)[ix]), ix) Now, as mentioned, the answer to second question is the same except for ix: ix <- c(2, 1, 3) aperm(array(c(aperm(Z, ix)) - c(t(Q)), dim(Z)[ix]), ix) -- Statistics & Software Consulting GKX Group, GKX Associates Inc. tel: 1-877-GKX-GROUP email: ggrothendieck at gmail.com ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.