Hi:
Try this:
labs <- c("abcdef","abcgg","tgthefdk","tgtijuel","tgtnjmoi","gbnt","dlift")
dat <- c(0.5,0.25,1,2,16,0.250,4)
dframe <- data.frame(labs, dat, stringsAsFactors = FALSE)
dframe$lab2 <- factor(substr(dframe$lab, 1, 3))
aggregate(dat ~ lab2, data = dframe, FUN = mean)
lab2 dat
1 abc 0.375000
2 dli 4.000000
3 gbn 0.250000
4 tgt 6.333333
HTH,
Dennis
On Fri, Jul 22, 2011 at 1:00 PM, alfredo <alfredote...@gmail.com> wrote:
> Hi Folks,
>
> Ran into something I'd really like to do in R simply/elegantly, but my R -
> coding skills seem surpassed. This is the thing. Imagine the following data:
>
> labs<-c("abcdef","abcgg","tgthefdk","tgtijuel","tgtnjmoi","gbnt","dlift")
> dat<-c(0.5,0.25,1,2,16,0.250,4)
> dframe<-data.frame(labs,dat)
>
> I would like to average the values in "dat" according to specific
> string/text in the name of their row names described by "labs". For example,
> average the values in "dat" if the first three (or more) letters in their
> corresponding "labs" are the same. This would give the following vector:
>
> 0.375000 6.333333 0.250000 4.000000 # in which 0.375 is the average of
> "abcdef" and "abcgg", etc.
>
> I hope I've made myself (kind'a) clear and apologise otherwise. Any ideas?
>
> Thanks for your help!
>
> A
>
> --
> View this message in context:
> http://r.789695.n4.nabble.com/averaging-rows-based-on-string-tp3687689p3687689.html
> Sent from the R help mailing list archive at Nabble.com.
>
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