Pei -
A file pattern can't contain a directory separator, but it's
easy to search for one outside the context of list.files. I think
grep('B/file2.txt',list.files(path = routeStr, all.files = TRUE,
full.names = TRUE, recursive = TRUE),value=TRUE)
should give you what you want.
- Phil Spector
Statistical Computing Facility
Department of Statistics
UC Berkeley
spec...@stat.berkeley.edu
On Tue, 19 Jul 2011, JIA Pei wrote:
Hi, all:
My folders are organized in such a way:
root
----branch1
---------------A
-----------------------file1.txt
-----------------------file2.txt
---------------B
-----------------------file1.txt
-----------------------file2.txt
----branch2
---------------A
-----------------------file1.txt
-----------------------file2.txt
---------------B
-----------------------file1.txt
-----------------------file2.txt
...
----branch100
---------------A
-----------------------file1.txt
-----------------------file2.txt
---------------B
-----------------------file1.txt
-----------------------file2.txt
I'd love to list all file2.txt from all subdirectories "B"s but not from
"A"s, how to do that?
I tried the following two
a) allResults <- list.files(path = routeStr, pattern = "file2.txt",
all.files = TRUE, full.names = TRUE, recursive = TRUE);
gives me 200 files in allResults, which is wrong. There should be only 100
files in allResults.
b) allResults <- list.files(path = routeStr, pattern = "B/file2.txt",
all.files = TRUE, full.names = TRUE, recursive = TRUE);
still wrong. It give me nothing, namely, 0 file(s) in allResults.
Can anybody help to solve this problem?
Best Regards
Pei
--
Pei JIA
Email: jp4w...@gmail.com
cell: +1 604-362-5816
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