Suppose I have following dataset : > head(data1) Date Return 1 03/31/00 0.14230650 2 04/28/00 -0.03276228 3 05/31/00 -0.06527890 4 06/30/00 -0.04999873 5 07/31/00 -0.01447902 6 08/31/00 0.22265729
Now I convert it to zoo object : > data11 = zoo(data1[,2], as.Date(data1[,1], format="%m/%d/%y")) > head(data11) 2000-03-31 2000-04-28 2000-05-31 2000-06-30 2000-07-31 2000-08-31 0.14230650 -0.03276228 -0.06527890 -0.04999873 -0.01447902 0.22265729 Clearly those are monthly data. Therefore I want to convert it to mm-yy format. I used following code : data111 = zoo(coredata(data11), format(index(data11), "%m/%y")) However what I got is that : > head(data111) 01/01 01/02 01/03 01/04 01/05 01/06 -0.001388889 -0.016274826 -0.047707664 0.001104362 -0.077961541 0.017637141 > tail(data111) 12/02 12/03 12/04 12/05 12/06 12/07 0.058660676 -0.018067833 -0.055569851 0.007142888 0.051162052 0.052643733 It is evident that month order has been changed. Can anyone here tell me how to get correct order like : 01/01, 02/01, 03/01.................. Your help is highly appreciated Regards, --------------------------------- [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.