Hello List
I'm trying to calculate the median period (in months) of a set of time
intervals (between two interventions).
I have been playing with the lubridate package to create the intervals but I
can't think of the right approach to get the median timeperiod.
Toy code:
library(lubridate)
test <- c('08-04-22', '08-07-28', '09-03-02', '09-03-03', '09-01-30',
'09-03-09', '10-02-24', '10-03-05')
test <- ymd(test)
intervals <- as.period(test[5:8] - test[1:4])
intervals
[1] 9 months and 8 days 7 months and 9 days 11 months and 22 days
[4] 1 year and 2 days
How can I convert this 'period' object to months? From there I think I should
just convert to 'numeric' and calculate the median.
Garrett if you're out there - great package but could you help please!?
Best
iain
> sessionInfo()
R version 2.13.0 (2011-04-13)
Platform: x86_64-pc-linux-gnu (64-bit)
locale:
[1] LC_CTYPE=en_GB.utf8 LC_NUMERIC=C
[3] LC_TIME=en_GB.utf8 LC_COLLATE=en_GB.utf8
[5] LC_MONETARY=C LC_MESSAGES=en_GB.utf8
[7] LC_PAPER=en_GB.utf8 LC_NAME=C
[9] LC_ADDRESS=C LC_TELEPHONE=C
[11] LC_MEASUREMENT=en_GB.utf8 LC_IDENTIFICATION=C
attached base packages:
[1] stats graphics grDevices utils datasets methods base
other attached packages:
[1] lubridate_0.2.4
loaded via a namespace (and not attached):
[1] plyr_1.5.2 stringr_0.4
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