1. Please always quote the original message when sending messages to
this *mailing list*.
2. Please send your answers and comments also to the original poster who
may not be aware you posted to the list.
Uwe Ligges
On 25.06.2011 06:55, jwehr wrote:
Thank you, Joshua!
I got what I was looking for using this command:
as.numeric(grepl("\\*$", qb$Player))
Where the variable name is "Player" in dataset "qb".
--
View this message in context:
http://r.789695.n4.nabble.com/Extract-character-from-the-end-of-a-string-tp3621732p3624124.html
Sent from the R help mailing list archive at Nabble.com.
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.