Hi: It's just an extra step:
y <- list(list(c(1,5),c(2,3,4)), list(c(1, 3, 4), c(5, 7))) lapply(seq_len(length(y)), function(i) lapply(y[[i]], min)) [[1]] [[1]][[1]] [1] 1 [[1]][[2]] [1] 2 [[2]] [[2]][[1]] [1] 1 [[2]][[2]] [1] 5 unlist(lapply(seq_len(length(y)), function(i) lapply(y[[i]], min))) [1] 1 2 1 5 HTH, Dennis On Sun, Jun 19, 2011 at 8:25 AM, jiliguala <jiligu...@mail.com> wrote: > > but in my case, the list is a two-variable list, list[[j]][[i]] > > when i use > > lapply(list, min) > > it appears > """Error in FUN(X[[1L]], ...) : invalid 'type' (list) of argument""" > > thanks > > -- > View this message in context: > http://r.789695.n4.nabble.com/how-to-get-the-miminum-value-in-the-list-tp3609013p3609433.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
