You almost solved your own problem with that last statement. Instead of comparing apples and oranges, you need to compare oranges and oranges:
> list(c(1,2,3)) %in% list(c(1,2,3), c(4,5,6)) [1] TRUE > list(c(1,2,3)) %in% list(c(1,2,9), c(4,5,6)) [1] FALSE Sarah On Mon, May 30, 2011 at 9:36 AM, Marcin Wlodarczak <mwlodarc...@uni-bielefeld.de> wrote: > > Hi, > > I need some help with this one: how do I check whether a vector is > already present in a list of vectors. > > I have seen %in% recommended in a similar case but that obviously does > not work here. > > c(1,2,3) %in% list(c(1,2,3), c(4,5,6)) > > returns > > [1] FALSE FALSE FALSE > > which makes sense since 1, 2 or 3 are not elements of that list. I don't > really know how to move from there though. > > Best wishes, > Marcin > -- Sarah Goslee http://www.functionaldiversity.org ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
