Try this approach:
> x <- c('18x.6','12x.9','302x.3')
> gsub("^(.*)\\..*", '\\1', x)
[1] "18x" "12x" "302x"
On Sun, May 29, 2011 at 8:10 PM, Matthew Keller <mckellerc...@gmail.com> wrote:
> hi all,
>
> I'm full of questions today :). Thanks in advance for your help!
>
> Here's the problem:
> x <- c('18x.6','12x.9','302x.3')
>
> I want to get a vector that is c('18x','12x','302x')
>
> This is easily done using this code:
>
> unlist(lapply(strsplit(x,".",fixed=TRUE),function(x) x[1]))
>
> So far so good. The problem is that x is a vector of length 132e6.
> When I run the above code, it runs for > 30 minutes, and it takes > 23
> Gb RAM (no kidding!).
>
> Does anyone have ideas about how to speed up the code above and (more
> importantly) reduce the RAM footprint? I'd prefer not to change the
> file on disk using, e.g., awk, but I will do that as a last resort.
>
> Best
>
> Matt
>
> --
> Matthew C Keller
> Asst. Professor of Psychology
> University of Colorado at Boulder
> www.matthewckeller.com
>
> ______________________________________________
> R-help@r-project.org mailing list
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
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