Thanks Henrique for this mail. It works fine. However I need one more
modification. When number of column is 1 then some error is coming :
> library(zoo)
> date.data = seq(as.Date("01/01/01", format = "%m/%d/%y"),as.Date("06/25/02",
> format = "%m/%d/%y"), by = 1)
> len = length(date.data)
> data1 = zoo(matrix(rnorm(len), nrow = len), date.data )
> head(data1)
2001-01-01 -1.5128990
2001-01-02 -0.2939971
2001-01-03 1.6387866
2001-01-04 -0.8107857
2001-01-05 0.7966224
2001-01-06 0.6007594
>
> lapply(split(data1, format(index(data1), "%m")), cov)
Error in FUN(X[[1L]], ...) : supply both 'x' and 'y' or a matrix-like 'x'
However I tried with an 'ifelse' condition :
> lapply(split(data1, format(index(data1), "%m")), ifelse(dim(data1)[1] > 1,
cov, var))
Still I am getting error. What to do?
Henrique Dallazuanna <[EMAIL PROTECTED]> wrote:
Perhaps something like this:
lapply(split(data1, format(index(data1), "%m")), cov)
On 27/02/2008, Megh Dal wrote:
> let create a 'zoo' object :
>
> library(zoo)
> date.data = seq(as.Date("01/01/01", format = "%m/%d/%y"), as.Date("06/25/02",
> format = "%m/%d/%y"), by = 1)
> len = length(date.data)
> data1 = zoo(matrix(rnorm(2*len), nrow = len), date.data )
> head(data1)
>
> Now I want to create an 3 dimensional array (suppose name " var.cov") where,
> var.cov[,,i] gives the Variance-covariance matrix for i-th month of data1.
> That is I want to calculate monthly variance-covariance matrix on
> non-overlapping rolling window basis.
>
> Any suggestion?
>
>
>
> ---------------------------------
>
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>
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>
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
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