I don't think filled.contour gives you access to the contour lines. If you use contourLines() to compute them, then you can draw them using code like this:

 contours <- contourLines(V2b,levels=paliers)
 for (i in seq_along(contours)) {
   x <- contours[[i]]$x
   y <- contours[[i]]$y
   lines( splines( seq_along(x), x)$y, splines( seq_along(y), y)$y )
}

but as I said, you won't get great results. A better way is to use a finer grid, e.g. by fitting a smooth surface to your set of points and using predictions from the model to interpolate.

Duncan Murdoch


On 17/05/2011 9:35 AM, Pierre Bruyer wrote:
I work with large datasets (10000 points) so I can't post them , but my 
function is :

create_map<- function(grd, level ,map_output, format = c("jpeg"), width_map = 
150, height_map = 150,...)
{       
                
        ##sp<- spline(x = grd[,1], y = grd[,2])

        grd2<- matrix(grd[,3], nrow = sqrt(length(grd[,3])), ncol = 
sqrt(length(grd[,3])), byrow = FALSE)
        
        V2b<- grd2

        
        ##creation of breaks for colors
        i<-1 
        paliers<- c(-1.0E300)
        while(i<=length(level[,1]))
        {
                paliers<- c(paliers,level[i,1])
                i<- i+1
        }
        paliers<- c(paliers, 1.0E300)
                
        ##scale color creation
        i<- 1
        colgraph<- c(rgb(255,255,255, maxColorValue = 255))
        while(i<=length(level[,2]))
        {
                colgraph<- c(colgraph, rgb(level[i,2],level[i,3],level[i,4], 
maxColorValue = 255))
                i<- i +1
        }

        ##user can choose the output format (default is jpeg)
        switch(format,
                png = png(map_output, width = width_map, height = height_map) ,
                jpeg = jpeg(map_output, width = width_map, height = height_map, 
quality = 100),
                bmp = bmp(map_output, width = width_map, height = height_map),
                tiff = tiff(map_output, width = width_map, height = height_map),
                jpeg(map_output, width = width_map, height = height_map))

        ## drawing map
        
        ##delete marge
        par(mar=c(0,0,0,0))
        filled.contour(V2b, col = colgraph, levels = paliers, asp = 1, axes = 
FALSE, ann = FALSE)
        dev.off()               

}

where grd is a xyz data frame,
map_output is the path+name of the output image file,
and level is a matrix like this :


level<- matrix(0,10,4)
level[1,1]<- 1.0000E+00
level[2,1]<- 3.0000E+00
level[3,1]<- 5.0000E+00
level[4,1]<- 1.0000E+01
level[5,1]<- 1.5000E+01
level[6,1]<- 2.0000E+01
level[7,1]<- 3.0000E+01
level[8,1]<- 4.0000E+01
level[9,1]<- 5.0000E+01
level[10,1]<- 7.5000E+01


level[1,2]<- 102
level[2,2]<- 102
level[3,2]<- 102
level[4,2]<- 93
level[5,2]<- 204
level[6,2]<- 248
level[7,2]<- 241
level[8,2]<- 239
level[9,2]<- 224
level[10,2]<- 153

level[1,3]<- 153
level[2,3]<- 204
level[3,3]<- 204
level[4,3]<- 241
level[5,3]<- 255
level[6,3]<- 243
level[7,3]<- 189
level[8,3]<- 126
level[9,3]<- 14
level[10,3]<- 0

level[1,4]<- 153
level[2,4]<- 204
level[3,4]<- 153
level[4,4]<- 107
level[5,4]<- 102
level[6,4]<- 33
level[7,4]<- 59
level[8,4]<- 63
level[9,4]<- 14
level[10,4]<- 51

Le 17 mai 2011 à 15:17, Duncan Murdoch a écrit :

>  On 17/05/2011 8:24 AM, Pierre Bruyer wrote:
>>  Thank you for your answer, but the function spline() (and a lot of other 
function in R)  can't take in its parameters the original contour which are define by 
a vector, i.e. :
>>
>
>  If you post some reproducible code to generate the contours, someone will 
show you how to use splines to interpolate them.
>
>  Duncan Murdoch
>
>>        ##creation of breaks for colors
>>        i<-1 
>>        paliers<- c(-1.0E300)
>>        while(i<=length(level[,1]))
>>        {
>>                paliers<- c(paliers,level[i,1])
>>                i<- i+1
>>        }
>>        paliers<- c(paliers, 1.0E300)
>>
>>
>>
>>  Le 17 mai 2011 à 13:05, Duncan Murdoch a écrit :
>>
>>  >   On 11-05-17 5:58 AM, Pierre Bruyer wrote:
>>  >>   I'm a French developer (so I am sorry if my english is not perfect). I 
have a problem to smooth the contours of a map. I have a dataset with 3 columns, x, y and 
z, where x and y are the coordinates of my points and z is evaluate to a qualitative 
elevation and his representation is a set of colors, which is define by levels.
>>  >>
>>  >>   The problem is the curve of my contour is so linear, and I would like 
a more continuous contour. I use the function fitted.contour to draw my map.
>>  >
>>  >   If you use a finer grid of x,y values you'll get shorter segments and 
they will look smoother.
>>  >
>>  >   You might be able to use a smooth interpolator (e.g. spline()) rather 
than linear interpolation, but those occasionally do strange things e.g.
>>  >
>>  >   x<- c(1:4, 5.9, 6:10)
>>  >   y<- c(1:4,   7, 6:10)
>>  >   plot(spline(x,y, n=200), type="l")
>>  >   points(x,y)
>>  >
>>  >   where one point is out of line with the others, but the curve 
overcompensates in order to stay smooth.
>>  >
>>  >   Duncan Murdoch
>>
>


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