Hello R-help,
Is there a way to get R to tell you the coefficients in a lm that it
wouldn't normally tell you because of identifiability constraints? For
instance, if you use contr.sum() to generate contrasts for a factor, say
## y <- some data
## x <- a factor with levels 1:6
contrasts(x) <- contr.sum(levels(x))
lm.1 <- lm(y ~ x)
how would one persuade summary.lm to give the coefficient for x6 as well
as x1 up to x5? I know in this case that x6 is minus the sum of x1 to
x5, but I am working on a problem where the constraints are very
complicated and it would be a real help to see all the coefficients.
Thanks in advance
James Lawrence.
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