On 02.05.2011 11:47, Matevž Pavlič wrote:
Hi,
When I use your code i get this :
dat<-data.frame(test=c("abc","cdf","dabc"))
d<-subset(dat,grepl(test,"abc"))
d <- subset(dat, grepl("abc", test))
d
Warning message:
In grepl(test, "abc") :
argument 'pattern' has length> 1 and only the first element will be used
d
test
1 abc
2 cdf
3 dabc
I can't seem to make it work. Also how would i use the grepl() to select only
those that are not like i.e. »GP«?
Use the negation:
d <- subset(dat, !grepl("abc", test))
Uwe Ligges
Thanks, m
From: Steven Kennedy [mailto:stevenkennedy2...@gmail.com]
Sent: Monday, May 02, 2011 11:30 AM
To: Matevž PavliÄ
Cc: r-help@r-project.org
Subject: Re: [R] subseting data
You can use grepl:
dat<-data.frame(test=c("abc","cdf","dabc"))
d<-subset(dat,grepl(test,"abc"))
d
test
1 abc
3 dabc
On Mon, May 2, 2011 at 7:03 PM, Matevž PavliÄ<matevz.pav...@gi-zrmk.si>
wrote:
Hi,
Is it possible (i am sure it is) to subset data from a data.frame on the basis of
SQL>LIKE< operator. I.e., i would like to subset a data where only values which
contains a string>GP< would be used?
Example:
Gp<-subset(DF, DF$USCS like>GP<)
This like of course is not working,
Thanks, m
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and provide commented, minimal, self-contained, reproducible code.
______________________________________________
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.