On 02.05.2011 11:47, Matevž Pavlič wrote:
Hi,



When I use your code i get this :



dat<-data.frame(test=c("abc","cdf","dabc"))

d<-subset(dat,grepl(test,"abc"))

d <- subset(dat, grepl("abc", test))



d

Warning message:

In grepl(test, "abc") :

   argument 'pattern' has length>  1 and only the first element will be used

d

   test

1  abc

2  cdf

3 dabc



I can't seem to make it work. Also how would i use the grepl() to select only 
those that are not like i.e. »GP«?


Use the negation:

d <- subset(dat, !grepl("abc", test))


Uwe Ligges






Thanks, m





From: Steven Kennedy [mailto:stevenkennedy2...@gmail.com]
Sent: Monday, May 02, 2011 11:30 AM
To: Matevž Pavlič
Cc: r-help@r-project.org
Subject: Re: [R] subseting data



You can use grepl:

dat<-data.frame(test=c("abc","cdf","dabc"))
d<-subset(dat,grepl(test,"abc"))
d
   test
1  abc
3 dabc




On Mon, May 2, 2011 at 7:03 PM, Matevž Pavlič<matevz.pav...@gi-zrmk.si>  
wrote:

Hi,



Is it possible (i am sure it is)  to subset data from a data.frame on the basis of 
SQL>LIKE<  operator. I.e., i would like to subset a data where only values which 
contains a string>GP<  would be used?



Example:



Gp<-subset(DF, DF$USCS like>GP<)



This like of course is not working,



Thanks, m


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and provide commented, minimal, self-contained, reproducible code.

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