That works like a charm! Thanks so much Duncan.
On Fri, Apr 29, 2011 at 6:37 PM, Duncan Murdoch <[email protected]>wrote:
> On 29/04/2011 9:34 PM, Miao wrote:
>
>> Thanks Duncan for clarifying this. I'm pretty a newbie to such type of
>> characters and special characters. In R's gsub() what regular
>> expressions shall I use to handle all these situations?
>>
>
> I don't know. This might work:
>
> gsub("[\x01-\x1f\x7f-\xff]", "", x)
>
> (i.e. the range from character 1 to character 31, and 127 to 255) but I
> don't know if our regular expression matcher will accept those characters.
>
> Duncan Murdoch
>
>
>>
>> On Fri, Apr 29, 2011 at 6:07 PM, Duncan Murdoch
>> <[email protected] <mailto:[email protected]>> wrote:
>>
>> On 29/04/2011 7:41 PM, Miao wrote:
>>
>> Hello,
>>
>> Can anyone help on gsub() in R? I have a string like something
>> below, and
>> wanted to delete all the strings with leading backslash,
>> including "\xa0On",
>> "\023, "\xab", and many others. How should I write a regular
>> expression
>> pattern in gsub()? I don't care how many characters following
>> backslash.
>>
>>
>>
>> If those are R strings, none of them contain a backslash. In R, a
>> backslash would always be printed as \\.
>>
>> \x is the introduction to a hexadecimal encoding for a character;
>> the next two characters show the hex digits. So your first string
>> contains a single character \xa0, the third one contains \xab, and
>> so on.
>>
>> The \023 is an octal encoding for a single character.
>>
>> Duncan Murdoch
>>
>>
>>
>> txt<- "Is This Thing\xa0On? http://bit.ly/jAbKem wait \023 for
>> people \xab
>> and be patient :"
>>
>> Thanks in advance,
>> Miao
>>
>> [[alternative HTML version deleted]]
>>
>> ______________________________________________
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>>
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>>
>>
>>
>>
>> --
>> proceed everyday
>>
>
>
--
proceed everyday
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