On 30/04/11 02:44, Alaios wrote:
Thanks a lot.
I finally used
M2<- M
M2[M< thresh]<- 0
M2[M>= thresh]<- 1
as I noticed that this one line
M2<- as.numeric( M[]< thresh )
vectorizes my matrix.
One more question I have two matrices that only differ slightly. What will be
the easiest way to compare and find the cells that are not the same?
(1) M2 <- 0 +(M >= thresh)
is one line (and is sexier! :-) ).
(2) which(A !=B, arr.ind = TRUE)
or (possibly more sensibly)
which (abs(A-B) > sqrt(.Machine$double.eps), arr.ind = TRUE)
should solve your ``One more question''.
cheers,
Rolf Turner
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