On Apr 29, 2011, at 6:47 AM, Mathias Walter wrote:

Hi,

I have large data frame with many columns. A short example is given below:

dataH
   host ms01 ms31 ms33 ms34
1  cattle    4   20    9    6
2   sheep    4    3    4    5
3  cattle    4    3    4    5
4  cattle    4    3    4    5
5   sheep    4    3    5    5
6    goat    4    3    4    5
7   sheep    4    3    5    5
8    goat    4    3    4    5
9    goat    4    3    4    5
10 cattle    4    3    4    5

Now I want to determine the the frequencies of every unique value in
every column depending on the host column.

It is quite easy to determine the frequencies in total with the
following command:

dataH2 <- dataH[,c(2,3,4,5)]
table(as.matrix(dataH2), colnames(dataH2)[col(dataH2)], useNA="ifany")

   ms01 ms31 ms33 ms34
3     0    9    0    0
4    10    0    7    0
5     0    0    2    9
6     0    0    0    1
9     0    0    1    0
20    0    1    0    0

But I cannot manage to get it dependent on the host.

I tried

xtabs(cbind(ms01, ms31, ms33, ms34) ~ ., dataH)

and many other ways but I'm not stressful.

I can get it for each column individually with

with(dataH, table(host, ms33))

      ms33
host     4 5 9
cattle 3 0 1
deer   0 0 0
goat   3 0 0
human  0 0 0
sheep  1 2 0
tick   0 0 0

But I do not want to repeat the command for every column. I need a
single table which can be plotted as a balloon plot, for instance.

You have obviously not given us the full data from which your "correct answer" was drawn, but see if this is going the right direction:

require(reshape)
> dataHm <- melt(dataH)
Using host as id variables
> xtabs(~host+value+variable, dataHm)
, , variable = ms01

        value
host     3 4 5 6 9 20
  cattle 0 4 0 0 0  0
  goat   0 3 0 0 0  0
  sheep  0 3 0 0 0  0

, , variable = ms31

        value
host     3 4 5 6 9 20
  cattle 3 0 0 0 0  1
  goat   3 0 0 0 0  0
  sheep  3 0 0 0 0  0

, , variable = ms33

        value
host     3 4 5 6 9 20
  cattle 0 3 0 0 1  0
  goat   0 3 0 0 0  0
  sheep  0 1 2 0 0  0

, , variable = ms34

        value
host     3 4 5 6 9 20
  cattle 0 0 3 1 0  0
  goat   0 0 3 0 0  0
  sheep  0 0 3 0 0  0


Does anybody knows how to achieve this?

--
Kind regards,
Mathias

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David Winsemius, MD
West Hartford, CT

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