Take vector x and a subset y:
x=1:10
y=c(4,5,7,9)
For each value in 'x', I want to know how many elements in 'y' are less than
'x'.
An example would be:
sapply(x,FUN=function(i) {length(which(y<i))})
[1] 0 0 0 0 1 2 2 3 3 4
But this solution is far too slow when x and y have lengths in the millions.
I'm certain an elegant (and computationally efficient) solution exists, but I'm
in the weeds at this point.
Any help is much appreciated.
Kevin
University of Manchester
Take two vectors x and y, where y is a subset of x:
x=1:10
y=c(2,5,6,9)
If y is removed from x, the original x values now have a new placement (index)
in the resulting vector (new):
new=x[-y]
index=1:length(new)
The challenge is: How can I *quickly* and *efficiently* deduce the new 'index'
value directly from the original 'x' value -- using only 'y' as an input?
In practice, I have very large matrices containing the 'x' values, and I need
to convert them to the corresponding 'index' if the 'y' values are removed.
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