hi , this can be done easily if (cond) expr
ex:
> for (i in 1: 4)+ {+ if(i==2) print("a")+ if(i==2) print("b")+ }
output : [1] "a"[1] "b"
but i want this
if (cond) expr1 expr 2
i tried this :
> for (i in 1: 4)+ {+ if(i==2) (print("b") && print("a"))+ }
output : [1] "b"Error in print("b") && print("a") : invalid 'x' type in 'x && y'
but i expect the same out put as before .
i am new at R . plz help .
Thanks , Tanvir
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